M4 June 2006 Q6
6.

Two small smooth spheres \(A\) and \(B\), of equal size and of mass \(m\) and \(2m\) respectively, are moving initially with the same speed \(U\) on a smooth horizontal floor. The spheres collide when their centres are on a line \(L\). Before the collision the spheres are moving towards each other, with their directions of motion perpendicular to each other and each inclined at an angle of 45\(^\circ\) to the line \(L\), as shown in Figure 2. The coefficient of restitution between the spheres is \(\tfrac{1}{2}\).
(a) Find the magnitude of the impulse which acts on \(A\) in the collision. (9)

The line \(L\) is parallel to and a distance \(d\) from a smooth vertical wall, as shown in Figure 3.
(b) Find, in terms of \(d\), the distance between the points at which the spheres first strike the wall. (5)

| Scheme | Marks |
|---|---|
| Form: \(\ I = m\left(v_2 + \dfrac{U}{\sqrt{2}}\right)\) | M1 A1 |
| CLM\((\uparrow)\colon\ \dfrac{2mU}{\sqrt{2}} - \dfrac{mU}{\sqrt{2}} = 2mv_1 + mv_2\) | |
| \(\dfrac{U}{\sqrt{2}} = 2v_1 + v_2\qquad (1)\) | M1 A1 |
| NIL: \(\ e\dfrac{2U}{\sqrt{2}} = \dfrac{U}{\sqrt{2}} = -v_1 + v_2\qquad (2)\) | M1 A1 |
| \(\Rightarrow \dfrac{3U}{\sqrt{2}} = 3v_2\) | M1 A1 |
| \(\Rightarrow I = m\left(\dfrac{U}{\sqrt{2}} + \dfrac{U}{\sqrt{2}}\right)\) | |
| \(= mU\sqrt{2}\) | A1 |
| (9) |
Notes
The published mark scheme for this paper is handwritten.
| Scheme | Marks |
|---|---|
| \(v_2 - v_1 = \dfrac{U}{\sqrt{2}}\qquad\) (Separation speed) | M1 |
| time to wall \(= \dfrac{d}{U/\sqrt{2}} = \dfrac{d\sqrt{2}}{U}\) | M1 A1 |
| \(\therefore\) Separation \(= \dfrac{d\sqrt{2}}{U} \times \dfrac{U}{\sqrt{2}} = d\) | M1 A1 |
| (5) | |
| (14 marks) |