M3 January 2007 Q2
2.

A uniform solid right circular cone has base radius \(a\) and semi-vertical angle \(\alpha\), where \(\tan\alpha = \tfrac{1}{3}\). The cone is freely suspended by a string attached at a point \(A\) on the rim of its base, and hangs in equilibrium with its axis of symmetry making an angle of \(\theta^\circ\) with the upward vertical, as shown in Figure 1.
Find, to one decimal place, the value of \(\theta\).

| Scheme | Marks |
|---|---|
| Height of cone \(= \dfrac{a}{\tan\alpha} = 3a\) | M1 A1 |
| Hence \(h = \tfrac{3}{4}a\) | ↓ M1 |
| \(\tan\theta = \dfrac{a}{\frac{3}{4}a} = \dfrac{4}{3} \Rightarrow \theta = 53.1^\circ\) | ↓ M1 A1 |
| (5) | |
| (5 marks) |
Notes
↓ marks a mark that depends on the M mark above it (an arrow in the scheme).
1st M1 (generous) allow any trig ratio to get height of cone (e.g. using sin)
3rd M1 For correct trig ratio on a suitable triangle to get \(\theta\) or complement (even if they call the angle by another name – hence if they are aware or not that they are getting the required angle)