4400 Higher November 2010 Paper 4 Q6
6 \(V = \dfrac{2}{3}hy^2\)
(a) \(h = 2.6\) \(\quad y = 1.5\)
Work out the value of \(V\). (2)
Work out the value of \(V\). (2)
(b) \(V = 35\) \(\quad y = 2.5\)
Work out the value of \(h\). (2)
Work out the value of \(h\). (2)
(c) Make \(y\) the subject of the formula \(V = \dfrac{2}{3}hy^2\) (2)
| Scheme | Marks |
|---|---|
| \(\frac{2}{3} \times 2.6 \times 1.5^2\) | M1 |
| 3.9 | A1 |
| (2) |
Notes
M1: for correct substitution
A1: cao
| Scheme | Marks |
|---|---|
\(35 = \frac{2}{3} \times h \times 2.5^2\) or \((h =)\ \dfrac{35}{\frac{2}{3} \times 2.5^2}\) oe | M1 |
| 8.4 | A1 |
| (2) |
Notes
M1: for correct substitution or correct rearrangement
A1: cao
| Scheme | Marks |
|---|---|
| \(y^2 = \dfrac{3V}{2h}\) | M1 |
| \(\sqrt{\dfrac{3V}{2h}}\) | A1 |
| (2) | |
| (6 marks) |
Notes
M1: for \(y^2 = \dfrac{3V}{2h}\) oe
A1: for \(\sqrt{\dfrac{3V}{2h}}\) or \(\pm\sqrt{\dfrac{3V}{2h}}\) oe