4400 Higher November 2008 Paper 3 Q7
7 Show that \(\dfrac{2}{5} \div \dfrac{4}{7} = \dfrac{7}{10}\)
(3)
| Scheme | Marks |
|---|---|
| \(\frac{2}{5} \times \frac{7}{4}\) or \(\frac{14}{35} \div \frac{20}{35}\) | B2 |
| \(\frac{14}{20}\) | B1 |
| (3) | |
| (3 marks) |
Notes
B2: for \(\frac{2}{5} \times \frac{7}{4}\)
(B1 for inverting second fraction ie \(\frac{7}{4}\))
or
B1 for 2 fractions with a denominator of 35 etc
B1 for correct numerators
B1: eg for \(\frac{14}{20}\) oe or correct cancelling