4400 Higher June 2009 Paper 4 Q1
1 Show that \(\dfrac{2}{3} \div \dfrac{5}{9} = 1\dfrac{1}{5}\)
(3)
| Scheme | Marks |
|---|---|
| \(\frac{2}{3} \times \frac{9}{5}\) or \(\frac{6a}{9a}\) and \(\frac{5a}{9a}\) \(\frac{6a}{9a} \div \frac{5a}{9a}\) | M2 |
| \(\frac{18}{15}\) or \(\frac{6}{5}\) | A1 |
| (3) | |
| (3 marks) |
Notes
M2: M1 for inverting 2nd fraction i.e. \(\frac{9}{5}\)
or
M1 2 correct fractions with common denominators of a multiple of 9
M2 correct numerators and intention to divide
A1: any fraction equivalent to \(1\frac{1}{5}\)
Do not allow decimal conversions