4400 Higher November 2004 Paper 4 Q12
12 Solve the simultaneous equations
\[6x - 5y = 13\] \[4x - 3y = 8\](4)
| Scheme | Marks |
|---|---|
| \(12x - 10y = 26\) or \(18x - 15y = 39\) | M1 |
| \(12x - 9y = 24\) or \(20x - 15y = 40\) | A1 |
| \(y = -2\) or \(2x = 1\) | M1 |
| \(\frac{1}{2}\), −2 | A1 |
| (4) | |
| (4 marks) |
Notes
M1: for coefficients of \(x\) or \(y\) the same followed by correct operation. Condone one arithmetical error
A1: cao
M1: (dep on 1st M1) for substituting for other variable
A1: cao