4MA0 Higher June 2017 Paper 3R Q3
3
Diagram NOT accurately drawn
\(ABCD\) is a parallelogram.
\(BEFC\) is a rhombus.
Angle \(DAB = 142^\circ\)
Angle \(CBE = 62^\circ\)
Calculate the value of \(x\).
(3)
| Scheme | Marks |
|---|---|
| Angle \(BCD = 142^\circ\) or Angle \(BCF = 180 - 62\) (\(=118^\circ\)) or Angle \(ABC = 180 - 142\) (=38) | M1 |
| 360 – 142 – “118” or “38” + 62 | M1 |
| 100 | A1 |
| (3) | |
| (3 marks) |
Notes
M1: for angle \(BCD = 142^\circ\) or
angle \(BCF = (180 - 62)^\circ\)
M1: for a complete method to find \(x\)