4MA0 Higher June 2016 Paper 4R Q10
10 Solve
\[\begin{aligned} 4x + 3y &= 6 \\ 3x + 5y &= -1 \end{aligned}\]Show clear algebraic working.
(4)
| Scheme | Marks |
|---|---|
| \(12x + 9y = 18\) \(12x + 20y = -4\) (\(11y = -22\)) or \(20x + 15y = 30\) \(9x + 15y = -3\) (\(11x = 33\)) | M1 |
| \(y = -2\) or \(x = 3\) | A1 |
| \(4x + 3 \times -2 = 6\) or \(4 \times 3 + 3y = 6\) | M1 |
| \(x = 3\), \(y = -2\) | A1 |
| (4) |
Notes
M1: for coefficients of \(x\) or \(y\) the same with the correct operation to eliminate one variable (allow one error) or for correct rearrangement of one equation followed by substitution in the other.
A1: ( dep on M1)
M1: (dep on M1) for substituting for the other variable or starting again to eliminate the other variable
A1: (dep on M1, M1)