4MA0 Higher June 2016 Paper 3R Q11
11 The line L passes through the point (3,1) and is parallel to the line with equation \(y = \dfrac{7}{2} - 2x\).
Find an equation for the line L.
(3)
| Scheme | Marks |
|---|---|
| gradient = −2 | M1 |
| \(1 = 3 \times \text{‘}(-2)\text{’} + c\) or \(y - 1 = \text{‘}{-2}\text{’}(x - 3)\) oe | M1ft |
| \(y = -2x + 7\) | A1oe |
| (3) |
Notes
M1: for \(m = -2\) stated or \(y = k - 2x\) where \(k \neq 7/2\)
M1ft: Correct substitution to find \(c\) for their gradient
A1oe: (M2 for \(-2x + 7\) or \(L = -2x + 7\))