4MA0 Higher June 2015 Paper 4 Q7
7
Show clear algebraic working. (3)
| Scheme | Marks |
|---|---|
| \(24 - 18y\) | B1 |
| (1) |
| Scheme | Marks |
|---|---|
| \(e(e + 4)\) | B1 |
| (1) |
Notes
B1: Allow \((e + 0)(e + 4)\) ignore missing bracket at end
| Scheme | Marks |
|---|---|
| Eg. \(7x - 2x = -3 - 8\) | M1 |
| \(5x = -11\) | M1 |
| −2.2 oe | A1 |
| (3) |
Notes
M1: for correct rearrangement with \(x\) terms on one side and numbers on the other or
the correct simplification of either \(x\) terms or numbers on one side in a correct equation
eg. \(5x + 8 = -3\) ; \(7x = 2x - 11\)
M1: Award also for \(-5x = 11\)
A1: −2.2 oe dependent on at least M1 awarded;
if no correct algebraic working then award no marks
| Scheme | Marks |
|---|---|
| \(y^2 + 10y - 2y - 20\) | M1 |
| \(y^2 + 8y - 20\) | A1 |
| (2) |
Notes
M1: for 3 correct terms out of 4
or for 4 correct terms ignoring signs
or for \(y^2 + 8y + c\) for any non-zero value of \(c\)
or for ... \(+ 8y - 20\)
A1: cao
| Scheme | Marks |
|---|---|
| \(4e^2 f(5e^3 f - 4)\) | B2 |
| (2) |
Notes
B2: B1 for a correct but incomplete factorised answer with a minimum of 2 out of 4, \(\boldsymbol{e^2}\) or \(\boldsymbol{f}\) outside the bracket, ie
\(4e^2(5e^3f^2 - 4f)\), \(4f(5e^5f - 4e^2)\), \(e^2f(20e^3f - 16)\), \(4ef(5e^4f - 4e)\), \(2e^2f(10e^3f - 8)\)
or \(4e^2f\)(a two term algebraic expression)