4MA0 Higher June 2014 Paper 4 Q12
12 The diagram shows triangle ADC.
Diagram NOT accurately drawn
E is a point on AD and B is a point on AC so that EB is parallel to DC.
\(AB = 14\) cm.
\(EB = 16\) cm.
\(DC = 20\) cm.
Calculate the length of BC.
(3)
| Scheme | Marks |
|---|---|
\(\dfrac{20}{16}\) (=1.25) or \(\dfrac{20}{16} \times 14\) oe (=17.5) or \(\dfrac{AC}{20} = \dfrac{14}{16}\) oe | M1 |
| eg. \(14 \times \dfrac{20}{16} - 14\) | M1 |
| 3.5 | A1 |
| (3 marks) |
Notes
M1: or for a correct scale factor
eg. \(\dfrac{20}{16}\) or \(\dfrac{16}{20}\) or 1.25 or 0.8 or \(\dfrac{14}{16}\) oe or \(\dfrac{16}{14}\) oe
M1: for complete method
Alternatively: M1 for 16 ÷ (20 – 16) = 4; M1 for complete method