4MA0 Higher June 2013 Paper 3 Q4
4

Diagram NOT accurately drawn
\(ABCDEF\) is a hexagon.
\(G\) is a point on \(AF\).
\(H\) is a point on \(BC\).
\(GH\) is parallel to \(AB\).
(a) Give a reason why \(x = 107\) (1)
(b) Work out the value of \(y\). (4)
| Scheme | Marks |
|---|---|
| corresponding (angle(s)) | B1 |
| (1) |
Notes
B1: oe eg \(x\) corresponds to angle \(A\);
corresponding to angle A
| Scheme | Marks |
|---|---|
| (6 − 2) × 180 or 4 × 180 or (2 × 6 − 4) × 90 or 8 × 90 or 120 × 6 or (180 − 60)×6 or 360 + 360 | M1 |
| 720 | A1 |
| “720” − (107 + 134 + 142 + 92 + 123) or “720” − 598 | M1 |
| 122 | A1 |
| (4) |
Notes
A1: M1 A1 for 720 seen
M1: dep on first M1
Alternative using exterior angles: 360−(73+46+38+88+57) M1 (condone one incorrect ext angle); 58 M1 A1 for 58 seen; 180 − “58” M1