4400 Higher June 2008 Paper 3 Q9
9
(a) Solve \(7(x - 1) = 5 - 2x\)
You must show sufficient working. (3)
You must show sufficient working. (3)
(b)
(i) Solve the inequality \(4x + 5 \leqslant 21\)
(ii) \(n\) is a positive integer.
Write down all the values of \(n\) which satisfy \(4n + 5 \leqslant 21\)
(4)Write down all the values of \(n\) which satisfy \(4n + 5 \leqslant 21\)
| Scheme | Marks |
|---|---|
| \(7x - 7 = 5 - 2x\) | M1 |
| \(7x + 2x = 5 + 7\) or \(9x = 12\) | M1 |
| \(1\frac{1}{3}\) oe | A1 |
| (3) |
Notes
M1: for \(7x - 7\) seen
M1: for \(7x + 2x = 5 + 7\) or \(9x = 12\) or for \(7x + 2x = 5 + 1\) or \(9x = 6\) following \(7x - 1 = 5 - 2x\)
A1: for \(1\frac{1}{3}\) oe inc \(\frac{4}{3}\), \(\frac{12}{9}\), \(1.\dot{3}\), 1.33
| Scheme | Marks |
|---|---|
| (i) \(4x \leqslant 16\) | M1 |
| \(x \leqslant 4\) | A1 |
| (ii) Answer: 1 2 3 4 | B2 |
| (4) | |
| (7 marks) |
Notes
M1: for \(4x \leqslant 16\)
A1: for \(x \leqslant 4\)
B2: B1 for 3 correct and none wrong or for 4 correct and 1 wrong