4MA0 Higher January 2015 Paper 3R Q5
5 On the grid, draw the graph of \(y = 3x + 2\) for values of \(x\) from –2 to 4
(4)
| Scheme | Marks |
|---|---|
| (−2, −4)(−1, −1)(0, 2)(1, 5)(2, 8) (3, 11)(4, 14) Answer: Correct line between \(x = -2\) and \(x = 4\) | B4 |
| (B3) | |
| (B2) | |
| (B1) | |
| (4 marks) |
Notes
B4: For a correct line between \(x = -2\) and \(x = 4\)
(B3): For a correct line through at least 3 of (−2, −4)(−1, −1)(0, 2)(1, 5)(2, 8)(3, 11)(4, 14) OR
for all of (−2, −4)(−1, −1)(0, 2)(1, 5)(2, 8)(3, 11)(4, 14) plotted but not joined
(B2): For at least 2 correct points plotted OR for a line drawn with a positive gradient through (0, 2) and a clear attempt to use a gradient of 3
(B1): For at least 2 correct points stated (may be in a table) OR
For a line drawn with a positive gradient through (0, 2) OR for a line with the correct gradient. NB a line joining (0, 2) to (3, 0) scores B0