4MA0 Foundation June 2017 Paper 2R Q13
13 On the grid, draw the graph of \(y = 2x - 1\) from \(x = -2\) to \(x = 3\)
(3)
| Scheme | Marks |
|---|---|
| (−2,−5) (−1,−3) (0,−1) (1, 1) (2, 3) (3, 5) Answer: Correct line between \(x = -2\) and \(x = 3\) | B3 |
| B2 | |
| B1 | |
| (3) | |
| (3 marks) |
Notes
B3: For a correct line between \(x = -2\) and \(x = 3\)
B2: For a correct line through at least 3 of (−2,−5) (−1,−3) (0,−1) (1, 1) (2, 3) (3, 5) or
For all of (−2,−5) (−1,−3) (0,−1) (1, 1) (2, 3) (3, 5) plotted but not joined.
B1: For at least 2 correct points stated (may be in a table) or
For a line drawn with a positive gradient through (0,−1) or
For a line with the correct gradient.
NB a line joining (0,−1) to (2, 0) scores B0