4MA0 Foundation June 2017 Paper 1R Q18

Diagram NOT accurately drawn

\(ABCD\) is a parallelogram.
\(BEFC\) is a rhombus.

Angle \(DAB = 142^\circ\)
Angle \(CBE = 62^\circ\)

Calculate the value of \(x\).

(3)

Mark scheme

Scheme	Marks
Angle \(BCD = 142^\circ\) or Angle \(BCF = 180 - 62\) (=\(118^\circ\)) or Angle \(ABC = 180 - 142\) (=38)	M1
360 − 142 − “118” or “38” + 62	M1
100	A1
	(3)
	(3 marks)

M1: for angle \(BCD = 142^\circ\) or angle \(BCF = (180 - 62)^\circ\)

M1: for a complete method to find \(x\)