4MA0 Foundation June 2015 Paper 1 Q10

Diagram NOT accurately drawn

\(ABCD\) is a straight line.
Triangle \(ABF\) is equilateral.
Angle \(ECD = 110^\circ\)
Angle \(BEC = 38^\circ\)

Work out the size of angle \(x\).

(3)

Mark scheme

Scheme	Marks
Angle \(ECB = 70\) or Angle \(ECB = 180 - 110\) or Angle \(CBE = 72\) or Angle \(CBE = 110 - 38\) or Angle \(CBE = 180 - (70 + 38)\) or Angle \(AFB = 60\) or Angle \(FAB = 60\) or Angle \(FBA = 60\)	M1
eg (Angle \(FBE\) =) \(180 - 60 - 72\)	M1
48	A1
	(3)
	Total 3 marks

M1: for correct method to find any angle in diagram
NB: Accept \(A\) in place of \(FAB\); accept \(F\) in place of \(AFB\)

M1: for a complete correct method