4MA0 Foundation June 2014 Paper 2R Q5
5 Here is a number machine.
Input → × 4 → + 3 → Output
(a) Work out the output when the input is 5 (1)
(b) Work out the input when the output is −5 (2)
The input is \(x\) and the output is \(y\).
(c) Write \(y\) in terms of \(x\). (2)
| Scheme | Marks |
|---|---|
| 23 | B1 |
| (1) |
| Scheme | Marks |
|---|---|
| (−5 − 3) ÷ 4 | M1 |
| −2 | A1 |
| (2) |
| Scheme | Marks |
|---|---|
| \(y = 4x + 3\) | B2 |
| (2) | |
| (Total 5 marks) |
Notes
B2: for \(y = 4x + 3\) oe
If not B2 then B1 for \(4x + 3\) or \(x = (y - 3) \div 4\)