4MA0 Foundation June 2014 Paper 1 Q10
10

Diagram NOT accurately drawn
The diagram shows a quadrilateral \(ABCD\).
The quadrilateral \(ABCD\) is made from two identical isosceles triangles, \(ABD\) and \(CBD\).
\(DA = DB = DC\).
Angle \(BAD\) = Angle \(BCD = 35^\circ\)
Angle \(ADC = x^\circ\)
Work out the value of \(x\).
(4)
| Scheme | Marks |
|---|---|
| ABD or CBD = 35 | M1 |
| (ADB or CDB) = 180 – 2 × 35 (=110) | M1 |
| (x =) 360 – 2 × “110” | M1 |
| 140 | A1 |
| (4) | |
| (4 marks) |
Notes
M1: can be marked on diagram
M1: can be marked on diagram
M1: dep on previous M1. ft from 110 above
A1: cao