4MA0 Foundation June 2013 Paper 1R Q19
19 Solve \(\quad x = \dfrac{7 - 2x}{3}\)
Show clear algebraic working.
(3)
| Scheme | Marks |
|---|---|
| \(3x = 7 - 2x\) | M1 |
| \(5x = 7\) or \(5x - 7 = 0\) | M1 |
| 1.4oe | A1 |
| (3) |
Notes
M1: or \(x = \dfrac{7}{3} - \dfrac{2x}{3}\)
M1: or \(\dfrac{5x}{3} = \dfrac{7}{3}\) or \(x + \dfrac{2x}{3} = \dfrac{7}{3}\)
A1: Answer dependent on at least M1