4MA0 Foundation January 2015 Paper 1R Q9
9

Diagram NOT accurately drawn
\(PQR\) is an isosceles triangle.
\(QRS\) is a straight line.
\(PQ = PR\).
Angle \(PRS = 118^\circ\)
Work out the value of \(x\).
(3)
| Scheme | Marks |
|---|---|
| 180 − 118 or 62 | M1 |
| 180 − 2 × '62' | M1 |
| 56 | A1 |
| (3) | |
| (3 marks) |
Notes
M1: (dep) or 118 − '62'