1MA0 Higher March 2013 Paper 2 Q14
14 \(A = 4bc\)
\(A = 100\)
\(b = 2\)
(a) Work out the value of \(c\). (2)
\[m = \sqrt{\frac{k + 1}{4}}\](b) Make \(k\) the subject of the formula. (3)
| Working | Answer | Mark | Notes |
|---|---|---|---|
| \(100 = 4 \times 2 \times c\) | 12.5 | 2 | M1 for correct substitution into formula A1 for 12.5 oe |
| Working | Answer | Mark | Notes |
|---|---|---|---|
| \(m^2 = \dfrac{k + 1}{4}\) \(4m^2 = k + 1\) \(k = 4m^2 - 1\) or \(2m = \sqrt{(k + 1)}\) \(4m^2 = k + 1\) \(k = 4m^2 - 1\) | \(k = 4m^2 - 1\) | 3 | M1 for correct method to clear fraction or remove square root sign M1 (dep) for a fully correct method to both clear fraction and remove square root sign A1 for \(k = 4m^2 - 1\) or \(k = (2m + 1)(2m - 1)\) |