1MA0 Higher June 2017 Paper 1 Q15
15
Diagram NOT accurately drawn
\(ADB\) and \(AEC\) are straight lines.
\(DE\) is parallel to \(BC\).
Angle \(ABC = 90^\circ\)
\(AC = 10\) cm.
\(BC = 6\) cm.
\(D\) is the midpoint of \(AB\).
Work out the area of trapezium \(BCED\). (4)
| Answer | Mark | Notes |
|---|---|---|
| 18 | 4 | M1 for correct initial use of Pythagoras eg (\(AB^2\) =) \(10^2 - 6^2\) (= 64) or \(AB = 8\) M1 (dep M1) for \(\text{``}\sqrt{64}\text{''} \div 2\) (= 4) M1 for method to find area of trapezium eg \(\dfrac{1}{2} \times \text{``}4\text{''} \times (6 \div 2 + 6)\) A1 cao OR M1 for correct initial use of Pythagoras eg (\(AB^2\) =) \(10^2 - 6^2\) (= 64) or \(AB = 8\) M1 (dep M1) for method to find area of \(\Delta ABC\) eg \(\tfrac{1}{2} \times \text{``}\sqrt{64}\text{''} \times 6\) (= 24) or area of \(\Delta AED\) \(\tfrac{1}{2} \times 6 \div 2 \times \text{``}4\text{''}\) (= 6) or \(24 \times \left(\tfrac{1}{2}\right)^2\) (= 6) M1 for a complete method to find area of \(EDBC\) e.g \(\tfrac{3}{4} \times \text{``}24\text{''}\) eg \(\text{``}24\text{''} - \text{``}6\text{''}\) A1 cao |