1MA0 Higher June 2012 Paper 1 Q11
11
Diagram NOT accurately drawn
The diagram shows a parallelogram.
The sizes of the angles, in degrees, are
\(2x\)
\(3x - 15\)
\(2x\)
\(2x + 24\)
Work out the value of \(x\). (3)
| Working | Answer | Mark | Notes |
|---|---|---|---|
| \(3x - 15 = 2x + 24\) \(x = 39\) OR \(2x + 3x - 15 + 2x + 2x + 24 = 360\) \(9x + 9 = 360\) \(9x = 351\) \(x = 39\) OR \(2x + 2x + 24 = 180\) \(4x + 24 = 180\) \(4x = 156\) \(x = 39\) OR \(2x + 3x - 15 = 180\) \(5x - 15 = 180\) \(5x = 195\) \(x = 39\) | 39 | 3 | M1 for forming an appropriate equation eg. \(3x - 15 = 2x + 24\) OR \(2x + 3x - 15 + 2x + 2x + 24 = 360\) OR \(2x + 2x + 24 = 180\) OR \(2x + 3x - 15 = 180\) OR \(2x + 3x - 15 = 2x + 2x + 24\) M1 (dep) for correct operation(s) to isolate \(x\) and non-\(x\) terms in an equation to get to \(ax = b\) A1 cao OR M2 for \(\dfrac{351}{9}\) oe or \(\dfrac{195}{5}\) oe or \(\dfrac{156}{4}\) oe A1 cao |