D2 June 2015 Q1
1. The tableau below is the initial tableau for a linear programming problem in \(x\), \(y\) and \(z\). The objective is to maximise the profit, \(P\).
| Basic variable | \(x\) | \(y\) | \(z\) | \(r\) | \(s\) | \(t\) | Value |
|---|---|---|---|---|---|---|---|
| \(r\) | 2 | –4 | 1 | 1 | 0 | 0 | 15 |
| \(s\) | 4 | 2 | –8 | 0 | 1 | 0 | 20 |
| \(t\) | 1 | –1 | 4 | 0 | 0 | 1 | 8 |
| \(P\) | –3 | 2 | 7 | 0 | 0 | 0 | 0 |
| Scheme | Marks | |||||||||||||||||||||||||||||||||||||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| M1 A1 M1 A1ft A1 | |||||||||||||||||||||||||||||||||||||||||||||
| (5) |
Notes
a1M1: Correct pivot located (4 in column \(x\)), attempt to divide row
a1A1: Pivot row correct including change of b.v.
a2M1: All values in one of the non-pivot rows correct or one of the non zero and one columns (\(y\), \(z\), \(s\) or value) correct following through their choice of pivot from column \(x\)
a2A1ft: Row operations used correctly at least twice, i.e. two of the non zero and one columns (\(y\), \(z\), \(s\) or value) correct following through their choice of pivot from column \(x\)
a3A1: CAO – no follow through – all values and row operations correctly stated – allow if row operations given in terms of old row 2 – ignore b.v. column for this mark
Pivoting on the 1 in the \(x\)-column
| b.v. | \(x\) | \(y\) | \(z\) | \(r\) | \(S\) | \(t\) | V |
|---|---|---|---|---|---|---|---|
| \(r\) | 0 | −2 | −7 | 1 | 0 | −2 | −1 |
| \(s\) | 0 | 6 | −24 | 0 | 1 | −4 | −12 |
| \(x\) | 1 | −1 | 4 | 0 | 0 | 1 | 8 |
| \(P\) | 0 | −1 | 19 | 0 | 0 | 3 | 24 |
Pivoting on the 2 in the \(x\)-column
| b.v. | \(x\) | \(y\) | \(z\) | \(r\) | \(s\) | \(t\) | V |
|---|---|---|---|---|---|---|---|
| \(x\) | 1 | −2 | 0.5 | 0.5 | 0 | 0 | 7.5 |
| \(s\) | 0 | 10 | −10 | −2 | 1 | 0 | −10 |
| \(t\) | 0 | 1 | 3.5 | −0.5 | 0 | 1 | 0.5 |
| \(P\) | 0 | −4 | 8.5 | 1.5 | 0 | 0 | 22.5 |
| Scheme | Marks |
|---|---|
| \(P + \frac{7}{2}y + z + \frac{3}{4}s = 15\) | B1ft |
| \(r = 5,\ s = 0,\ t = 3\) | B1 |
| (2) | |
| 7 marks |
Notes
b1B1ft: Follow their profit equation from (a) dependent on scoring both M marks in (a)
b2B1: CAO (no follow through) for slack variables (\(r = 5\), \(s = 0\), \(t = 3\))