D2 June 2006 Q3
3. A college wants to offer five full-day activities with a different activity each day from Monday to Friday. The sports hall will only be used for these activities. Each evening the caretaker will prepare the hall by putting away the equipment from the previous activity and setting up the hall for the activity next day. On Friday evening he will put away the equipment used that day and set up the hall for the following Monday.
The 5 activities offered are Badminton (\(B\)), Cricket nets (\(C\)), Dancing (\(D\)), Football coaching (\(F\)) and Tennis (\(T\)). Each will be on the same day from week to week.
The college decides to offer the activities in the order that minimises the total time the caretaker has to spend preparing the hall each week.
The hall is initially set up for Badminton on Monday.
The table below shows the time, in minutes, it will take the caretaker to put away the equipment from one activity and set up the hall for the next.
| To | ||||||
|---|---|---|---|---|---|---|
| Time | \(B\) | \(C\) | \(D\) | \(F\) | \(T\) | |
| From | \(B\) | – | 108 | 150 | 64 | 100 |
| \(C\) | 108 | – | 54 | 104 | 60 | |
| \(D\) | 150 | 54 | – | 150 | 102 | |
| \(F\) | 64 | 104 | 150 | – | 68 | |
| \(T\) | 100 | 60 | 102 | 68 | – | |
A possible ordering of activities is
| Monday | Tuesday | Wednesday | Thursday | Friday |
|---|---|---|---|---|
| \(B\) | \(C\) | \(D\) | \(F\) | \(T\) |
| Scheme | Marks |
|---|---|
| Each activity must be visited once and then we return to the starting activity, this must be done in a minimum time | B2, 1, 0 |
| (2) |
Notes
B2 cao – all 3 bits in the context
B1 cloze ‘Bod’ is B1 (e.g. not in context; just ‘each activity once’ – but not all 3; …)
| Scheme | Marks |
|---|---|
| \(108 + 54 + 150 + 68 + 100 = 480\) minutes (= 8 hours) | M1 A1 |
| (2) |
Notes
M1 (maybe implicit) attempting to add 5 values
A1 cao
| Scheme | Marks |
|---|---|
| Use nearest neighbour B F T C D B | M1 A1 |
| \(64 + 68 + 60 + 54 + 150 = 396\) minutes (6.6 hours) | A1 |
| (3) |
Notes
M1 each vertex visited once – either NN or 2 x mst-shortcut (BD)
A1 cao incl return to B (BFTCDB)
A1 cao (396)
(Corrected from the printed mark scheme: the time in hours is printed as “67 hours”; 396 minutes is 6.6 hours.)
| Scheme | Marks |
|---|---|
![]() | |
| CT, TF, CD (Prim or Kruskal) | M1 A1 |
| \(182 + 64 + 100 = 346\) minutes | M1 A1ft |
| (4) | |
| (11 marks) |
Notes
M1 Finding correct minimum spanning tree (maybe implicit) 182 sufficient
A1 cao tree or 182
M1 adding 2 least arcs to B i.e. 100 and 64 only
A1ft cao ft from their m.s.t. value i.e. 164 and their tree length
