C2 June 2013 (R) Q2
2.\[y = \frac{x}{\sqrt{(1 + x)}}\]
| \(x\) | 1 | 1.1 | 1.2 | 1.3 | 1.4 | 1.5 |
|---|---|---|---|---|---|---|
| \(y\) | 0.7071 | 0.7591 | 0.8090 | 0.9037 | 0.9487 |
You must show clearly each stage of your working. (4)
| Scheme | Marks |
|---|---|
| \(\{x = 1.3\}\ \ y = 0.8572\) (only) | B1 cao |
| (1) |
Notes
B1: 0.8572 cao
| Scheme | Marks |
|---|---|
| \(\dfrac{1}{2} \times 0.1\ldots\ldots..\) | B1 |
| \(\{0.7071 + 0.9487 + 2(0.7591 + 0.8090 + \text{"}0.8572\text{"} + 0.9037)\}\) | M1 |
| \(\ldots\{0.7071 + 0.9487 + 2(0.7591 + 0.8090 + \text{"}0.8572\text{"} + 0.9037)\}\) | A1ft |
| \(\{0.05(8.3138)\} = 0.41569 =\) awrt 0.416 | A1 |
| (4) | |
| Total 5 |
Notes
B1 for using \(\tfrac{1}{2} \times 0.1\) or 0.05 or equivalent.
M1 It needs the first bracket to contain first \(y\) value plus last \(y\) value and the second bracket to be multiplied by 2 and to be the summation of the remaining \(y\) values in the table with no additional values. If the only mistake is a copying error or is to omit one value from 2nd bracket this may be regarded as a slip and the M mark can be allowed ( An extra repeated term forfeits the M mark however). M0 if values used in brackets are \(x\) values instead of \(y\) values
A1ft for the correct bracket \(\{\ldots\ldots\}\) following through candidate’s \(y\) value found in part (a).
NB: Separate trapezia may be used : B1 for 0.05, M1 for 1/2 \(h(a + b)\) used 4 or 5 times (and A1ft if it is all correct ) Then A1 as before. (Equivalent correct formulae may be used)
Special case: Bracketing mistake
\(0.05 \times (0.7071 + 0.9487) + 2(0.7591 + 0.8090 + \text{"}0.8572\text{"} + 0.9037)\) scores B1 M1 A0 A0 (usually for 6.74079) unless the final answer implies that the calculation has been done correctly (then full marks can be given).