Higher June 2025 Paper 2R Q10
10 A straight line, L, is parallel to the line with equation \(y = 2 - 5x\)
The line L passes through the point \((0, 6)\)
Find an equation of the line L
(2)
| Scheme | Marks |
|---|---|
| eg \(y = -5x\;(+ k)\) or \(y - a = -5(x - b)\) or eg \(y = mx + 6\) or \(y - 6 = m(x - 0)\) or eg \(-5x + 6\) or \(\mathbf{L} = -5x + 6\) | M1 |
| Correct answer scores full marks (unless from obvious incorrect working) Answer: \(y = -5x + 6\) | A1 |
| (2) | |
| (2 marks) |
Notes
M1: for the equation of any line with gradient \(-5\) other than \(y = 2 - 5x\)
or
for the equation of any line passing through the point \((0, 6)\)
or
the correct line missing ‘\(y =\)’ or with the wrong subject
A1: oe equation eg \(y = 6 - 5x\) or \(y - 6 = -5(x - 0)\)
or \(y + 5x = 6\)