Higher June 2025 Paper 2R Q1
1
(a) Factorise fully \(18c - 45cd\) (2)
(b) Solve \(\dfrac{5 - 2x}{6} = 3x - 4\)
Show clear algebraic working. (3)
Show clear algebraic working. (3)
| Scheme | Marks |
|---|---|
| \(9c(2 - 5d)\) | B2 |
| (2) |
Notes
B2: for \(9c(2 - 5d)\) or \(-9c(5d - 2)\)
(B1 for \(9(2c - 5cd)\) or \(c(18 - 45d)\) or \(3c(6 - 15d)\) or \(3(6c - 15cd)\)
or \(9c(p + qd)\) where \(p\) and \(q\) are non-zero integers
or \((2 - 5d)\) as a factor)
| Scheme | Marks |
|---|---|
eg \(5 - 2x = 18x - 24\) or \(\dfrac{5}{6} - \dfrac{2}{6}x = 3x - 4\) | M1 |
\(5 + 24 = 18x + 2x\) oe or \(29 = 20x\) oe or \(\dfrac{5}{6} + 4 = \dfrac{2}{6}x + 3x\) oe | M1ft |
| Working required Answer: 1.45 | A1 |
| (3) | |
| (5 marks) |
Notes
M1: for removal of the fraction and correctly multiplying out RHS by 6 in an equation
or
separating fractions on the LHS in an equation
M1ft: dep on 4 terms
for correctly rearranging their 4 term equation for terms in \(x\) on one side of the equation and number terms on the other
A1: dep on M1
oe eg \(\dfrac{29}{20}\) or \(1\dfrac{9}{20}\)