Higher June 2025 Paper 1R Q7
7 Change a speed of \(50x\) metres per second to a speed in kilometres per hour.
(3)
| Scheme | Marks |
|---|---|
\(50x \div 1000\) (= \(0.05x\)) oe or \(50x \times 60 \times 60\) (= \(180\,000x\)) oe or \(50x \div \dfrac{1}{3600}\) (= \(180\,000x\)) oe or \(50x \div 1000 \times 60\) (= \(3x\)) or \(\dfrac{3600}{1000}\) or \(\dfrac{18}{5}\) or 3.6 or \(\dfrac{1000}{3600}\) or \(\dfrac{5}{18}\) or 0.277(77…) | M1 |
eg \(\dfrac{50x \times 60 \times 60}{1000}\) oe or \(50x \times 3.6\) oe or \(50x \div \dfrac{1000}{3600}\) oe or 180 | M1 |
| Correct answer scores full marks (unless from obvious incorrect working) Answer: \(180x\) | A1 |
| (3) | |
| (3 marks) |
Notes
M1: Condone omission of \(x\) for this mark
M1: for a complete method including \(x\)
or for an answer of 180