Higher June 2024 Paper 2R Q7
7 \(\dfrac{3^{-2} \times 3^5}{3^{10}} = 3^n\)
Find the value of \(n\)
(2)
| Scheme | Marks |
|---|---|
eg \(3^3\) or \(\left(3^{-2}\right) \times 3^{-5}\) or \(\dfrac{3^3}{\left(3^{10}\right)}\) or \(\dfrac{\left(3^5\right)}{3^{12}}\) or \(\dfrac{\left(3^{-2}\right)}{3^5}\) or \(3^{-12}\left(\times 3^5\right)\) oe or – 2 + 5 – 10 oe or – 12 + 5 oe or 3 – 10 oe | M1 |
| Working not required, so correct answer scores full marks (unless from obvious incorrect working) Answer: –7 | A1 |
| (2) | |
| (2 marks) |
Notes
M1: for a correct application of an index rule as a first step
or
a correct calculation for \(n\)
A1: Allow \(3^{-7}\)