Higher June 2024 Paper 2R Q12
12
Diagram NOT accurately drawn
In the diagram, \(ABC\) and \(AED\) are straight lines.
\(BE\) is parallel to \(CD\)
\(AE = 10\) cm \(\qquad\) and \(\qquad CD = 1.5 \times BE\)
(a) Work out the length of \(ED\) (2)
\(AB = (2x + 5)\) cm and \(BC = (3x - 5)\) cm
(b) Work out the value of \(x\) (2)
| Scheme | Marks |
|---|---|
| \((AD =)\, 10 \times 1.5\) (= 15) oe | M1 |
| Working not required, so correct answer scores full marks (unless from obvious incorrect working) Answer: 5 | A1 |
| (2) |
| Scheme | Marks |
|---|---|
\((2x + 5) + (3x - 5) = 1.5 \times (2x + 5)\) oe or \(5x = 1.5 \times (2x + 5)\) oe or \(5x = 3x + 7.5\) oe or \(\dfrac{3x - 5}{2x + 5} = \dfrac{1}{2}\) oe | M1 |
| Working not required, so correct answer scores full marks (unless from obvious incorrect working) Answer: 3.75 | A1 |
| (2) | |
| (4 marks) |
Notes
M1: for a correct equation for \(x\)
A1: oe eg \(\dfrac{15}{4}\) or \(3\dfrac{3}{4}\)