Higher June 2023 Paper 2 Q19
19 Express \(\;3x^2 - 6x + 5\;\) in the form \(\;a(x - b)^2 + c\)
(3)
| Scheme | Marks |
|---|---|
| \(3(x^2 - 2x)\)….. or \(3(x^2 - 2x + \ldots..)\) oe or | M1 |
| \(3(x - 1)^2\)…… or \(3\left[(x - 1)^2 \ldots\ldots\right]\) oe | M1 |
| Correct answer scores full marks (unless from obvious incorrect working) Answer: \(3(x - 1)^2 + 2\) | A1 |
| (3) | |
| (3 marks) |
Notes
M1: (where …… is any number or no number)
M1: (where …… is any number or no number)
A1: (if student continues to solve a quadratic equation, ISW)
19 ALT
| Scheme | Marks |
|---|---|
| \(ax^2 - 2abx + ab^2 + c\) | M1 |
| Any 2 of the following: \(a = 3\) or \(2ab = 6\) or \(ab^2 + c = 5\) oe | M1 |
| Correct answer scores full marks (unless from obvious incorrect working) Answer: \(3(x - 1)^2 + 2\) | A1 |
| (3 marks) |
Notes
M1: for multiplying out \(a(x - b)^2 + c\) to obtain \(ax^2 - 2abx + ab^2 + c\) oe
M1: for equating coefficients with any 2 of \(a = 3\) or \(2ab = 6\) or \(ab^2 + c = 5\) oe seen
A1: (if student continues to solve a quadratic equation, ISW)