Higher June 2023 Paper 1 Q15
15
(a) \(\sqrt{2} \div \dfrac{8^3}{16^{\frac{3}{2}}} = 2^n\)
Work out the value of \(n\)
Show your working clearly. (3)
Work out the value of \(n\)
Show your working clearly. (3)
(b) Find 4% of \(\;4.5 \times 10^{157}\)
Give your answer in standard form. (3)
Give your answer in standard form. (3)
| Scheme | Marks |
|---|---|
| \(\sqrt{2} = 2^{\frac{1}{2}}\) or \(8^3 = 2^9\) or \(16^{\frac{3}{2}} = 2^6\) | M1 |
| M1 | |
| Working required Answer: −2.5 | A1 |
| (3) |
Notes
M1: for one of \(\sqrt{2} = 2^{\frac{1}{2}}\) or \(8^3 = 2^9\) or \(16^{\frac{3}{2}} = 2^6\)
M1: for all of
\(\sqrt{2} = 2^{\frac{1}{2}}\) and \(8^3 = 2^9\) and \(16^{\frac{3}{2}} = 2^6\)
OR \(2^{\frac{1}{2}} \div 2^3\)
A1: oe, dep on M1
| Scheme | Marks |
|---|---|
| \(0.04 \times 4.5 \times 10^{157}\) oe | M1 |
| \(4 \times 10^{-2} \times 4.5 \times 10^{157}\) (= \(18 \times 10^{155}\)) or \(0.18 \times 10^{157}\) oe | M1 |
| Correct answer scores full marks (unless from obvious incorrect working) Answer: \(1.8 \times 10^{156}\) | A1 |
| (3) | |
| (6 marks) |
Notes
A1: SCB1 for \(18 \times 10^{156} = 1.8 \times 10^{157}\)
or \(18 \times 10^{157} = 1.8 \times 10^{158}\)