Higher June 2022 Paper 1R Q10
10 Line L is drawn on the grid.
Find an equation for L
Give your answer in the form \(y = mx + c\)
(3)
| Scheme | Marks |
|---|---|
\(3 \div 2\) \(\left(= 1.5\text{ or }\dfrac{3}{2}\right)\) or eg \(\dfrac{5 - -1}{4 - 0}\) or \(c = -1\) | M1 |
| \(y = \text{``}{1.5}\text{''}x\;(+ c)\) or \(y = mx - 1\) or eg \(y - 5 = m(x - 4)\) | M1 |
| \(y = \dfrac{3}{2}x - 1\) | A1 |
| (3) | |
| (3 marks) |
Notes
M1: for correct method to find gradient or the correct value of \(c\)
for gradient, may see a correct calculation or \(\dfrac{3}{2}\) oe or \(1.5x\;(+ c)\) oe
for value of \(c\), allow \(c = -1\), \(y = -1\), (\(L\) =) \(mx - 1\) oe
M1: for use of \(y = mx + c\) with either \(m\) or \(c\) correct (NB: \(m \ne 0\))
or for (\(L\) =) \(1.5x - 1\) oe
A1: oe eg \(y = 1.5x - 1\)