Higher June 2018 Paper 2R Q14
14 \(128 = 4^{2x} \times 2^x\)
Work out the value of \(x\).
(3)
| Scheme | Marks |
|---|---|
| \(2^7 = 4^{2x} \times 2^x\) or \(128 = (2^2)^{2x} \times 2^x\) | M1 |
| \(7 = 2(2x) + x\) | M1 |
| 1.4 | A1 |
| (3) | |
| (3 marks) |
Notes
M1: Replacing 128 by \(2^7\) or 4 by \(2^2\)
A1: oe