Higher June 2018 Paper 2 Q5
5 In the diagram below, \(P\) and \(Q\) are points on a circle with centre \(O\).

Diagram NOT accurately drawn
\(QT\) is a tangent to the circle.
Angle \(OPQ\) = 18°
Work out the size of angle \(PQT\).
Give a reason for each stage of your working.
(3)
| Scheme | Marks |
|---|---|
| \(\angle OQT = 90^\circ\) and \(\angle OQP = 18^\circ\) or 90 – 18 | M1 |
| 72 | A1 |
| Angle between tangent and radius (or diameter) is 90 degrees | B1 |
| (3) | |
| (3 marks) |
Notes
M1: For 90° and 18° correctly identified in the working or on the diagram or for 90 – 18 or for other fully correct method
B1: Correct reason for 90° angle
[If used alternate segment theorem]