Higher June 2018 Paper 2 Q15
15 \(e\) = 8.31 correct to 2 decimal places
\(f\) = 0.65 correct to 2 decimal places
Work out the lower bound for the value of \(e - f\)
Show your working clearly.
(2)
| Scheme | Marks |
|---|---|
| \(8.305 - 0.655\) | M1 |
| Working required Answer: 7.65 | A1 |
| (2) | |
| (2 marks) |
Notes
M1: For either bound correct (used or seen). Accept \(0.654\dot{9}\)
A1: dep on correct method shown