Higher June 2018 Paper 2 Q10
10 \(\dfrac{8}{2^7} = 2^n\)
(a) Find the value of \(n\). (2)
\((13^{-6})^4 \times 13^5 = 13^k\)
(b) Find the value of \(k\). (2)
| Scheme | Marks |
|---|---|
| \(\dfrac{2^3}{2^7}\) or \(2^3 \times 2^{-7}\) or \(\dfrac{1}{2^4}\) or \(\dfrac{1}{16}\) and \(16 = 2^4\) | M1 |
| −4 | A1 |
| (2) |
Notes
A1: Accept \(2^{-4}\)
| Scheme | Marks |
|---|---|
| \(13^{-24} \times 13^5\) | M1 |
| −19 | A1 |
| (2) | |
| (4 marks) |
Notes
M1: for \(13^{-24}\) or for \(k = -6 \times 4 + 5\)
A1: Accept \(13^{-19}\)