Higher June 2018 Paper 1 Q18
18

The diagram shows the curve with equation \(y = \mathrm{f}(x)\)
The coordinates of the minimum point of the curve are (−2, −1)
(a) Write down the coordinates of the minimum point of the curve with equation
(i) \(y = \mathrm{f}(x - 5)\)
(ii) \(y = \dfrac{1}{2}\mathrm{f}(x)\) (2)
The graph of \(y = a\sin(x - b)^\circ + c\) for \(-90 \leqslant x \leqslant 450\) is drawn on the grid below.

(b) Find the value of \(a\), the value of \(b\) and the value of \(c\). (3)
| Scheme | Marks |
|---|---|
| (i) (3, −1) | B1 |
| (ii) (−2, −0.5) oe | B1 |
| (2) |
| Scheme | Marks |
|---|---|
| e.g. 2, 90, 1 | B3 |
| (3) | |
| (5 marks) |
Notes
B3: for all 3 correct values
e.g. 2, 90, 1 or −2, 270, 1
If not B3 then B2 for any 2 correct values
NB. 2 values from 2, 90, 1 OR 2 values from −2, 270, 1
NB: accept a value of (90 + 360n) in place of 90 or (270 + 360n) in place of 270 where n is an integer (could be negative)
If not B2 then B1 for any 1 correct value or the graph of \(y = \sin x^\circ\) for \(0 \leqslant x \leqslant 360\)