Higher January 2023 Paper 1R Q12
12 Solve \(\;2^{-4x} = 32\)
(2)
| Scheme | Marks |
|---|---|
| \(2^{-4x} = 2^5\) or \(-4x = 5\) or \(-\dfrac{4}{5}x = 1\) oe | M1 |
Correct answer scores full marks (unless from obvious incorrect working) Answer: \(-\dfrac{5}{4}\) | A1 |
| (2) | |
| (2 marks) |
Notes
A1: oe allow eg \(\dfrac{5}{-4}\)