Higher January 2021 Paper 2 Q1
1 A train takes 6 hours 39 minutes to travel from New Delhi to Kanpur.
The train travels a distance of 429 km.
Work out the average speed of the train.
Give your answer in km/h correct to one decimal place.
(3)
| Scheme | Marks |
|---|---|
6 hrs 39 mins = 6.65 (hrs) or \(6\dfrac{39}{60}\) or \(6\dfrac{13}{20}\) or \(\dfrac{133}{20}\) or 399 (mins) | B1 |
| Average speed = \(\dfrac{429}{6.65}\) oe eg \(\dfrac{429}{399} \times 60\) | M1 |
| Correct answer scores full marks (unless from obvious incorrect working) Answer: 64.5 | A1 |
| (3) | |
| (3 marks) |
Notes
M1: Use of \(S = D \div T\) (use of their time in hours)
[allow 429 ÷ 6.39 if B0 awarded]
A1: Awrt 64.5