Higher January 2021 Paper 1 Q21
21 A curve has equation \(y = \mathrm{f}(x)\)
The coordinates of the minimum point on this curve are \((-9, 15)\)
(a) Write down the coordinates of the minimum point on the curve with equation
(i) \(y = \mathrm{f}(x + 3)\)
(ii) \(y = \dfrac{1}{3}\mathrm{f}(x)\) (2)
The graph of \(y = a\cos(x + b)^\circ\) for \(0 \leqslant x \leqslant 360\) is drawn on the grid below.

Given that \(a \gt 0\) and that \(0 \lt b \lt 360\)
(b) find the value of \(a\) and the value of \(b\). (2)
| Scheme | Marks |
|---|---|
| (i) Answer: \((-12, 15)\) | B1 |
| (ii) Answer: \((-9, 5)\) | B1 |
| (2) |
| Scheme | Marks |
|---|---|
| \(a = 2\) and \(b = 90\) | B2 |
| (2) | |
| (4 marks) |
Notes
B2: for both values correct
(B1 for \(a = 2\) or \(b = 90\)
or \(a = -2\) and \(b = -90\))