Higher January 2021 Paper 1 Q20
20 A and B are two similar solids.
Diagram NOT accurately drawn
A has a volume of 1836 cm3
B has a volume of 4352 cm3
B has a total surface area of 1120 cm2
Work out the total surface area of A.
(3)
| Scheme | Marks |
|---|---|
\(\sqrt[3]{\dfrac{4352}{1836}}\) or \(\dfrac{4}{3}\) or 1.33(33...) or 4:3 or \(\sqrt[3]{\dfrac{1836}{4352}}\) or \(\dfrac{3}{4}\) or 0.75 or 3:4 | M1 |
| e.g. \(1120 \div \left(\text{“}\dfrac{4}{3}\text{”}\right)^2\) oe or \(1120 \times \left(\text{“}\dfrac{3}{4}\text{”}\right)^2\) oe | M1 |
| Correct answer scores full marks (unless from obvious incorrect working) Answer: 630 | A1 |
| (3) | |
| (3 marks) |
Notes
M1: for a correct length scale factor or a correct length ratio
M1: (dep on M1) for a correct method to work out the surface area of A