Higher January 2021 Paper 1 Q15
15
\[a = \dfrac{v - u}{t}\]\(v = 9.6\) correct to 1 decimal place
\(u = 3.8\) correct to 1 decimal place
\(t = 1.84\) correct to 2 decimal places
Calculate the upper bound for the value of \(a\).
Give your answer as a decimal correct to 2 decimal places.
Show your working clearly.
(3)
| Scheme | Marks |
|---|---|
| 9.55 or 9.65 or 3.75 or 3.85 or 1.835 or 1.845 | B1 |
| \(a = \dfrac{UB_v - LB_u}{LB_t}\) e.g. \(a = \dfrac{9.65 - 3.75}{1.835}\) (= 3.2152...) | M1 |
| Working required Answer: 3.22 | A1 |
| (3) | |
| (3 marks) |
Notes
B1: accept \(9.64\dot{9}\) for 9.65, \(3.84\dot{9}\) for 3.85, \(1.844\dot{9}\) for 1.845
M1: for correct substitution of
\(9.6 \lt UB_v \leqslant 9.65\)
and \(3.75 \leqslant LB_u \lt 3.8\)
and \(1.835 \leqslant LB_t \lt 1.84\)
A1: accept 3.21 – 3.22 from correct working