Higher January 2019 Paper 2R Q10
10
(a) Simplify fully \(\left(16x^8y^6\right)^{\frac{1}{2}}\) (2)
(b) Solve \(\dfrac{8 - 2x}{3} - \dfrac{2x - 3}{2} = 4\)
Show clear algebraic working. (3)
Show clear algebraic working. (3)
(c) Make \(f\) the subject of \(m = \sqrt{\dfrac{1}{3}ef}\) (2)
| Scheme | Marks |
|---|---|
| \(4x^4y^3\) | B2 |
| (2) |
Notes
B2: B1 for 2 correct terms of 3 in a product
| Scheme | Marks |
|---|---|
e.g. \(2(8 - 2x) - 3(2x - 3) = 4 \times 6\) or \(\dfrac{2(8 - 2x)}{6} - \dfrac{3(2x - 3)}{6} = 4\) or \(\dfrac{16 - 4x}{6} - \dfrac{6x - 9}{6} = 4\) or \(\dfrac{2(8 - 2x) - 3(2x - 3)}{6} = 4\) or \(\dfrac{-10x + 25}{6} = 4\) oe | M1 |
| e.g. \(16 - 4x - 6x + 9 = 24\) or \(-10x + 25 = 24\) oe | M1 |
| 0.1 | A1 |
| (3) |
Notes
M1: For method to deal with fractions
eg. finds a common denominator (6 or a multiple of 6)
or
multiplies by common multiple in a correct equation.
Condone one error in expansion
M1: For method to expand brackets and multiplies by common denominator in a correct equation.
Condone one error in expansion
A1: oe dep on M1
| Scheme | Marks |
|---|---|
| \(m^2 = \dfrac{1}{3}ef\) | M1 |
| \(f = \dfrac{3m^2}{e}\) | A1 |
| (2) | |
| (7 marks) |
Notes
M1: for squaring the \(m\)
A1: oe must have \(f =\)