Foundation November 2020 Paper 2 Q13
13 The diagram shows the plan of Sophia’s gym floor.
Diagram NOT accurately drawn
Sophia is going to paint all the gym floor.
Each tin of paint she is going to use covers an area of 20 m²
There is a special offer on the paint that Sophia is going to buy.
| Special Offer 1 tin for $13 4 tins for $40 |
Work out the least amount of money that Sophia has to pay in order to buy all the paint she needs.
Show your working clearly.
(5)
| Scheme | Marks |
|---|---|
eg \(\dfrac{1}{2} \times (20 + 26) \times 12\) (= 276) or \(12 \times 20 + \dfrac{1}{2} \times (26 - 20) \times 12\) (= 276) or \(12 \times 26 - \dfrac{1}{2} \times (26 - 20) \times 12\) (= 276) | M2 |
| “276” ÷ 20 (= 13.8) | M1 |
| eg 3 × $40 + 2 × $13 (= $146) or 14 × $13 (= $182) or 4 × $40 (= $160) | M1 |
| 146 | A1 |
| (5) | |
| (5 marks) |
Notes
M2: complete method to find the area of the shape
M1 for method to find the area of a rectangle 12 × 20 (= 240) or 12 × 26 (= 312) or the area of the triangle \(\dfrac{1}{2} \times (26 - 20) \times 12\) (= 36)
M1: (indep) method to find the number of tins for their area ft any value from a calculation that includes at least two of 20, 26 & 12
M1: method to calculate a cost for their number of tins dep on previous M1 (NB: use \(n\) × $40 where \(n\) is the next multiple of 4 greater than the number of tins needed, divided by 4)
A1: cao dep on accurate figures