Foundation June 2025 Paper 2R Q13

EdexcelCurrent spec7 marksFactorising Substitution

(a) Factorise \(\quad 15 - 5x\) (1)

\(d = 5p + 7r\)

(b) Work out the value of \(p\) when \(d = 35\) and \(r = 2\) (3)

Sweets are sold in small packets and large packets.

There are 12 sweets in a small packet.
There are 25 sweets in a large packet.

Ben buys \(m\) small packets of sweets and \(n\) large packets of sweets.

(c)

(i) Write an expression, in terms of \(m\) and \(n\), for the total number of packets of sweets Ben buys. (1)

(ii) Write an expression, in terms of \(m\) and \(n\), for the total number of sweets Ben buys. (2)

Scheme	Marks
\(5(3 - x)\)	B1
	(1)

Mark scheme (b)

Scheme	Marks
\(35 = 5 \times p + 7 \times 2\) or \(5p = d - 7r\) or \(\dfrac{d}{5} = p + \dfrac{7}{5}r\) oe	M1
\(5p = 35 -\) “14” or \(5p = 21\) or \(-5p = -35 +\) “14” or \(-5p = -21\) or (\(p =\)) \(\dfrac{35 - \text{“}14\text{”}}{5}\) or (\(p =\)) \(\dfrac{-35 + \text{“}14\text{”}}{-5}\) oe	M1
Correct answer scores full marks (unless from obvious incorrect working) Answer: \(\dfrac{21}{5}\)	A1
	(3)

Notes

M1: oe
for a correct substitution in an equation
or for a correct first step in re-arranging

M1: oe
for rearranging to find the value of \(5p\) or the value of \(-5p\) or a complete method to find the value of \(p\)

A1: oe eg 4.2

Scheme	Marks
\(m + n\)	B1
	(1)

Mark scheme (c)(ii)

Scheme	Marks
\(12m + 25n\)	B2
	(2)
	(7 marks)

Notes

B2: for final answer
\(12m + 25n\) or \(25n + 12m\)

(B1 for \(12m\) or \(25n\))

For B2 or B1, condone use of \(s\) and \(l\) for \(m\) and \(n\) respectively