Foundation June 2025 Paper 2 Q7
7 2 cupcakes and 5 doughnuts cost \(\$\)4.50
3 cupcakes cost \(\$\)2.25
Work out the cost of 1 doughnut.
(4)
| Scheme | Marks |
|---|---|
2.25 ÷ 3 (= 0.75) or 225 ÷ 3 (= 75) or \(\dfrac{2}{3} \times 2.25\) (= 1.5(0)) or \(\dfrac{2}{3} \times 225\) (= 150) or \(6c + 15d = 13.5(0)\) and \(6c = 4.5(0)\) oe or \(6c + 15d = 1350\) and \(6c = 450\) oe | M1 |
| 4.50 – 2 × “0.75” (= 3) or 450 – 2 × “75” (= 300) or \(15d = 9\) oe or \(15d = 900\) oe | M1 |
| “3” ÷ 5 or “300” ÷ 5 (= 60) or 9 ÷ 15 or 900 ÷ 15 (= 60) | M1 |
| Working not required, so correct answer scores full marks (unless from obvious incorrect working) Answer: 0.6(0) | A1 |
| (4) | |
| (4 marks) |
Notes
M1: for a correct method to find the cost of 1 cupcake
Allow \(\dfrac{1}{3} = 0.33\ldots\) or \(\dfrac{2}{3} = 0.66\ldots\) truncated or rounded
or
for setting up two equations where the coefficients of \(c\) are equal
\(c\) = cupcakes and \(d\) = doughnuts or the use of 2 different letters (may not be defined)
M1: for a correct method to find the cost of the 5 doughnuts
or
for finding an equation for \(d\)
M1: for a correct method to find the cost of 1 doughnut
A1: or \(\$\) crossed out and 60 cents
SCB2 for 4.50 – 2(3 ÷ 2.25) (= 1.83...) and “1.83...” ÷ 5 (= 0.36…)
OR
450 – 2(3 ÷ 225) (= 449.9...) and “449.9…” ÷ 5 (= 89.9…)
SCB1 for 4.50 – 2(3 ÷ 2.25) (= 1.83...)
OR
450 – 2(3 ÷ 225) (= 449.9...)