Foundation June 2025 Paper 1R Q5
5
(a) Simplify \(\quad 4e \times 7f\) (1)
(b) Simplify \(\quad d \times d \times d \times d \times d\) (1)
(c) Simplify \(\quad 3a + 2k + a - 7k\) (2)
(d) Solve \(\quad x + 6 = 15\) (1)
(e) Solve \(\quad 2r - 9 = 14\) (2)
| Scheme | Marks |
|---|---|
| \(28ef\) | B1 |
| (1) |
| Scheme | Marks |
|---|---|
| \(d^5\) | B1 |
| (1) |
| Scheme | Marks |
|---|---|
| \(4a - 5k\) | B2 |
| (2) |
Notes
B2: for \(4a - 5k\)
(B1 for \(4a\) or \(-5k\) or \(4a + -5k\))
| Scheme | Marks |
|---|---|
| 9 | B1 |
| (1) |
| Scheme | Marks |
|---|---|
| \(2r = 14 + 9\) or \(2r = 23\) oe or (14 + 9) ÷ 2 or 2 × 11.5 – 9 = 14 | M1 |
| Correct answer scores full marks (unless from obvious incorrect working) Answer: 11.5 | A1 |
| (2) | |
| (7 marks) |
Notes
M1: for a correct first step
or a correct calculation for \(r\)
A1: for 11.5 or \(\dfrac{23}{2}\) or \(11\dfrac{1}{2}\)